Assume that 1. the hour and minute hands of a clock move without jerking. 2. the clock shows a time between 8 o'clock and 9 o'clock. 3. the two hands of the clock are one above the other. After how many minutes (nearest integer) will the two hands be again lying one above the other?

1. **Analyze the Ask:** The question asks for the time duration between two consecutive overlaps ('one above the other').\n2. **Intuitive Logic:** Imagine the hands meeting at 12:00. The next time they meet is slightly after 1:00. Why? Because when the minute hand completes 60 minutes (returning to 12), the hour hand has moved to 1. The minute hand takes about 5 extra minutes to catch the hour hand. So the answer must be slightly more than 60+5 = 65 minutes.\n3. **Exact Verification (Optional but robust):** The relative gain is 55 minutes spaces in 60 minutes. To gain 60 minute spaces (one full lap), it takes (60/55)*60 = 720/11 minutes.\n4. **Calculation:** 720/11 is equal to 65 and 5/11 minutes. \n5. **Rounding:** 5/11 is roughly 0.45. So the exact time is ~65.45 minutes. The nearest integer is 65.\n6. **Elimination:** Options are 60, 62, 65, 67. 60 is too small (hour hand moves away). 62 is too small. 67 is too large. 65 is the only logical choice based on the '60 + 5' intuition.