Four persons, Alok, Bhupesh, Chander and Dinesh have a total of ₹ 100 among themselves. Alok and Bhupesh between them have as much money as Chander and Dinesh between them, but Alok has more money than Bhupesh; and Chander has only half the money that Dinesh has. Alok has in fact ₹ 5 more than Dinesh has. Who has the maximum amount of money?

Let's solve this intuitively. We have a total of ₹100. \n\n1. **The Big Split**: The problem states Alok and Bhupesh together have the same amount as Chander and Dinesh. \n - So, (A + B) = (C + D). \n - Since the total is 100, each pair must have exactly **₹50**.\n\n2. **Analyze Group 2 (Chander & Dinesh)**: They have ₹50 total. \n - Chander has half of Dinesh. This is a 1:2 ratio. \n - Splitting ₹50 into three parts means each part is roughly 16.6. \n - So, **Dinesh has ~33.3** and Chander has ~16.6.\n\n3. **Analyze Group 1 (Alok & Bhupesh)**: They also have ₹50 total.\n - We are told **Alok has ₹5 more than Dinesh**. \n - Since Dinesh has ~33.3, **Alok has 33.3 + 5 = 38.3**.\n - Consequently, Bhupesh has the remainder (50 - 38.3), which is roughly 11.7.\n\n4. **Final Comparison**: \n - Alok: ~38.3\n - Dinesh: ~33.3\n - Chander: ~16.6\n - Bhupesh: ~11.7\n\n Comparing the values, Alok clearly has the maximum amount.