How many consecutive zeros are there at the end of the integer obtained in the product 1² × 2⁴ × 3⁶ × 4⁸ × ... × 25⁵⁰?
A
(a) 50
B
(b) 55
C
(c) 100
D
(d) 200
Correct Answer: Option D
Explanation
1. **Recall PYQ Context (2020)**: From solving the 2020 question on trailing zeros, I know that 'consecutive zeros' are formed by pairs of 2 and 5. In a sequence like this, 2s are abundant, so 5 is the 'Limiting Factor' [5]