If the numerator and denominator of a proper fraction are increased by the same positive quantity which is greater than zero, the resulting fraction is
A
always less than the original fraction
B
always greater than the original fraction
C
always equal to the original fraction
D
such that nothing can be claimed definitely
Correct Answer: Option B
Explanation
To solve this in the most elegant way, we use the 'Substitution Strategy' which was heavily emphasized in the 2018 exam right before this year [22], [37].\n\n1. **Pick a simple Proper Fraction**: The definition says Numerator 0.5, the fraction has increased.\n\n4. **Verify (Optional)**: Just to be sure, let's try 2/3 (0.66). Add 1 to both -> 3/4 (0.75). It increased again. \n\nBy using this 'Smart Number Substitution' [34], we can clearly see the value always increases. The logic is that adding numbers pulls the fraction towards 1. Since a proper fraction starts below 1, it must go up.