Number 136 is added to 5B7 and the sum obtained is 7A3, where A and B are integers. It is given that 7A3 is exactly divisible by 3. The only possible value of B is
A
2
B
5
C
7
D
8
Correct Answer: Option D
Explanation
Let's solve this like a smart student who has analyzed the 2018 paper [60].
1. **Look at the Hundreds Column:**
We have $1 ( ext{from } 136) + 5 ( ext{from } 5B7)$. Normally, $1 + 5 = 6$.
But the res